Here's the question:
A restaurant wants to hire cooks and waiters at a minimum wage cost. The average monthly salary of a cook is $2000 and the average monthly salary of a waiter is $800. The restaurant can accomodate up to 25 staff and needs at least 20 to run properly. They must have at least 9 waiters, and may have up to 6 waiters for every 4 cooks. How many cooks and how many waiters should the camp hire to minimize cost?
Here's my equation to set it up:
c = # of cooks
w = # of waiters
c+w =%26lt; 25
c+w =%26gt; 20
w =%26gt; 9
6w =%26lt; 4c
Cost = C = 2000c + 800w
Then I did the Minimization Simplex method and placed all of these formulas in the simplex tableau, but I keep going around in circles and receiving negatives at the bottom of the tableau. What have I done wrong?
Is this Minimization problem set up correctly?
Your equation for "up to 6 waiters for every 4 cooks" is wrong. It should be 4w ≤ 6c (from w≤ 6(c/4)), or 6c - 4w ≥ 0
Sunday, August 2, 2009
Proof with set laws?
use only the set laws, to prove the following result for all sets A,B, C:
(A - B) - C = A - ( B u C )
( the u on the right hand side is a union symbol)
Proof with set laws?
I'll use u to denote the union (as you have). I'll use ^ to denote the intersection of two sets, and I'll use a small c to denote the complement of a set (for example, Ac will mean the complement of A).
(A - B) - C = (A ^ Bc) - C (definition of set difference)
(A ^ Bc) - C = (A ^ Bc) ^ Cc (definition of set difference)
(A ^ Bc) ^ Cc = A ^ (Bc ^ Cc) (associativity of intersection)
A ^ (Bc ^ Cc) = A ^ (B u C)c (DeMorgan's Law)
A ^ (B u C)c = A - (B u C) (definition of set difference).
I hope this is of some help to you.
lady palm
(A - B) - C = A - ( B u C )
( the u on the right hand side is a union symbol)
Proof with set laws?
I'll use u to denote the union (as you have). I'll use ^ to denote the intersection of two sets, and I'll use a small c to denote the complement of a set (for example, Ac will mean the complement of A).
(A - B) - C = (A ^ Bc) - C (definition of set difference)
(A ^ Bc) - C = (A ^ Bc) ^ Cc (definition of set difference)
(A ^ Bc) ^ Cc = A ^ (Bc ^ Cc) (associativity of intersection)
A ^ (Bc ^ Cc) = A ^ (B u C)c (DeMorgan's Law)
A ^ (B u C)c = A - (B u C) (definition of set difference).
I hope this is of some help to you.
lady palm
How do you calculate the variance and standard deviation of PI using C++?
after setting a C++ program to estimate the value of PI using the Monte Carlo random numbers method, how can you modify the code to calculate the variance and the standard deviation of PI?
How do you calculate the variance and standard deviation of PI using C++?
From this site:
http://www.eveandersson.com/pi/monte-car...
Using the Monte Carlo method you end up with this calculation:
pi = (4*M)/N
where
M = number of points inside the circle
N = number of total points used
From Wikipedia:
http://en.wikipedia.org/wiki/Standard_de...
Suppose we wished to find the standard deviation of the set of the numbers 4 and 8:
Step 1: find the arithmetic mean (or average) of 4 and 8
(4 + 8) / 2 = 6
Step 2: find the difference between each number and the mean
4 − 6 = −2
8 − 6 = 2
Step 3: square each of the differences
(−2)^2 = 4
(2)^2 = 4
Step 4: sum the obtained squares
4 + 4 = 8.
Step 5: divide the sum by the count of numbers (here we have two numbers)
8 / 2 = 4
-- So, the variance is 4 --
Step 6: take the non-negative square root of the quotient
sqrt(4)=2
-- So, the standard deviation is 2 --
The standard deviation is the square root of the variance, so step 5 produces the variance and step 6 produces the standard devation.
What you need to do:
1) Calculate the value of PI using increasing numbers of points and store each result. So, try 100 points, then 200 points, then 300 points, etc... and build up an array of different values for pi.
2) Write a function to calculate the variance and standard deviation. You'll need to pass in your pi array and then follow the above formula in a loop for each value.
Hope this helps!
How do you calculate the variance and standard deviation of PI using C++?
From this site:
http://www.eveandersson.com/pi/monte-car...
Using the Monte Carlo method you end up with this calculation:
pi = (4*M)/N
where
M = number of points inside the circle
N = number of total points used
From Wikipedia:
http://en.wikipedia.org/wiki/Standard_de...
Suppose we wished to find the standard deviation of the set of the numbers 4 and 8:
Step 1: find the arithmetic mean (or average) of 4 and 8
(4 + 8) / 2 = 6
Step 2: find the difference between each number and the mean
4 − 6 = −2
8 − 6 = 2
Step 3: square each of the differences
(−2)^2 = 4
(2)^2 = 4
Step 4: sum the obtained squares
4 + 4 = 8.
Step 5: divide the sum by the count of numbers (here we have two numbers)
8 / 2 = 4
-- So, the variance is 4 --
Step 6: take the non-negative square root of the quotient
sqrt(4)=2
-- So, the standard deviation is 2 --
The standard deviation is the square root of the variance, so step 5 produces the variance and step 6 produces the standard devation.
What you need to do:
1) Calculate the value of PI using increasing numbers of points and store each result. So, try 100 points, then 200 points, then 300 points, etc... and build up an array of different values for pi.
2) Write a function to calculate the variance and standard deviation. You'll need to pass in your pi array and then follow the above formula in a loop for each value.
Hope this helps!
Find a new set of integers.?
Suppose a,b,c are distinct integers. Define a new set of integers, called the "sugmented set of { a,b,c }" by constructing {ab+c, ac+b, bc+a, a(b+c), b(a+c), c(a+b)}. What set {a,b,c} has its augmented set {25,29,79,36,91,99}?
Find a new set of integers.?
ab+bc=91
ab+c=25
therefore bc-c=66
c(b-1)=66
c=11 or 6
b= 12 or 7
If c = 11, then b = 7, and a = 2 (ab+c=25 =%26gt; 7a+11=25)
Find a new set of integers.?
ab+bc=91
ab+c=25
therefore bc-c=66
c(b-1)=66
c=11 or 6
b= 12 or 7
If c = 11, then b = 7, and a = 2 (ab+c=25 =%26gt; 7a+11=25)
In New Yahoo mail Beta, how can I change weather display setting from 'F' to 'C'?
I tried changing Weather Display setting on my weather page from 'F'arenheat to 'C'elcius degree. still it won't work.
In New Yahoo mail Beta, how can I change weather display setting from 'F' to 'C'?
F-32/180=C/100
e.g,104degree farenheat
104-32/180=c/100or C=72X100/180=40degrees
!04*F=40*C
In New Yahoo mail Beta, how can I change weather display setting from 'F' to 'C'?
F-32/180=C/100
e.g,104degree farenheat
104-32/180=c/100or C=72X100/180=40degrees
!04*F=40*C
I got an answer from XLman telling me to dump everything in C:documents and setting, etc. There is no place?
There is no place to dump C:documents and settings, etc. There is no place to type in anything. Would XLman please clarify? Thank you so very much.
I got an answer from XLman telling me to dump everything in C:documents and setting, etc. There is no place?
What XLMan wanted you to do is to clear your temporary files to see if that helped with your Yahoo Messenger issue. If you open My Computer on your desktop, double click on C: then on Documents and Settings. Look for your folder in this next window - if you normally log in with a specific user name, double click on it. Then, double click on Local Settings, and then double click on Temp. Select everything (hit Ctrl+A) and then delete everything. If you're not sure of your login situation, you can probably go through all of the folders that shows up when you look at Documents and Settings.
If that doesn't help, you can always try to uninstall Yahoo Messenger. Leave it uninstalled if you don't use it, but if you want to reinstall it, make sure you download the latest version and take notes if anything else strange happens to your computer.
Reply:What was the initiall ? - I could help ya
snow of june
I got an answer from XLman telling me to dump everything in C:documents and setting, etc. There is no place?
What XLMan wanted you to do is to clear your temporary files to see if that helped with your Yahoo Messenger issue. If you open My Computer on your desktop, double click on C: then on Documents and Settings. Look for your folder in this next window - if you normally log in with a specific user name, double click on it. Then, double click on Local Settings, and then double click on Temp. Select everything (hit Ctrl+A) and then delete everything. If you're not sure of your login situation, you can probably go through all of the folders that shows up when you look at Documents and Settings.
If that doesn't help, you can always try to uninstall Yahoo Messenger. Leave it uninstalled if you don't use it, but if you want to reinstall it, make sure you download the latest version and take notes if anything else strange happens to your computer.
Reply:What was the initiall ? - I could help ya
snow of june
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C):?
Prove if true or give a counter example if false:
For all sets A,B and C , A * (B U C) = (A* B) U (A* C):
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C):?
Well, if by "*" you mean intersection, its true.
Here's an informal proof. Suppose A is just those elemenst in A alone, B in B alone, C in C alone, AB those in A and B but not C, etc.
So A*(BuC) = AB and AC and ABC
A*B = AB and ABC
A*C = AC and ABC
So A*B u A*C = AB and AC and ABC
QED.
.
For all sets A,B and C , A * (B U C) = (A* B) U (A* C):
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C):?
Well, if by "*" you mean intersection, its true.
Here's an informal proof. Suppose A is just those elemenst in A alone, B in B alone, C in C alone, AB those in A and B but not C, etc.
So A*(BuC) = AB and AC and ABC
A*B = AB and ABC
A*C = AC and ABC
So A*B u A*C = AB and AC and ABC
QED.
.
Thermostat for C200 Matic '96. Which is the best temperature setting for this thermostat? 71 C, 87 C or what?
Sometime, mostly vendors offer the thermostat with setting temp of 71 C instead of (higher than this or 87 C). Based on the reference I got, the current engine (newer not old engine) will run in better performance when apply the higher range of this thermostat i.e. 82 C to 91 C. Beside that, combustion will be more effisien and redue the polutant. Would you please tell us about the proper thermostat temp setting selection? thx.
Thermostat for C200 Matic '96. Which is the best temperature setting for this thermostat? 71 C, 87 C or what?
All kinds of engines work at their best between 80 an 90 Celsius.Surpassing 90 a little bit is not a crime against humanity.I have some engines that work great at 95
Reply:Stay with stock,the computer, needs a stock thermo.
Reply:i have that at my moms house, her place isn't big so 71 i good to keep i Constance setting
Thermostat for C200 Matic '96. Which is the best temperature setting for this thermostat? 71 C, 87 C or what?
All kinds of engines work at their best between 80 an 90 Celsius.Surpassing 90 a little bit is not a crime against humanity.I have some engines that work great at 95
Reply:Stay with stock,the computer, needs a stock thermo.
Reply:i have that at my moms house, her place isn't big so 71 i good to keep i Constance setting
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C)?
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C)
Prove if true or give a counter example if false:
For all sets A,B and C , A * (B U C) = (A* B) U (A* C):
Note: * means "times or multiply"
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C)?
How do you multiply sets? Do you perhaps mean intersection?
Prove if true or give a counter example if false:
For all sets A,B and C , A * (B U C) = (A* B) U (A* C):
Note: * means "times or multiply"
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C)?
How do you multiply sets? Do you perhaps mean intersection?
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C):\
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C):?
Prove if true or give a counter example if false:
For all sets A,B and C , A * (B U C) = (A* B) U (A* C):
Note: * means "times or multiply"
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C):\
The answer would depend on the type of sets you're dealing wtih along with the definition of "multiply". But generally, this equation is true for most sets you will deal with.
sweet pea
Prove if true or give a counter example if false:
For all sets A,B and C , A * (B U C) = (A* B) U (A* C):
Note: * means "times or multiply"
Prove if true or give a counter example if false: For all sets A,B and C , A * (B U C) = (A* B) U (A* C):\
The answer would depend on the type of sets you're dealing wtih along with the definition of "multiply". But generally, this equation is true for most sets you will deal with.
sweet pea
Why we should parallel the D.G.sets for power generation? Any presentation on E.G.C.P.( woodward) for parallel
we have 500kvad.g.sets. I have to give a presentation on paralleling of d.g.sets with E.G.C.P.(WOODWARD) . Any presentation on paralleling of d.g.sets in auto mode and advantages of EGCP over manual paralleling. cost of e.g.c.p and pay back and advantages of e.g.c.p.Simple presentation on power point is requested
Why we should parallel the D.G.sets for power generation? Any presentation on E.G.C.P.( woodward) for parallel
There are a few Woodward EGCP models around. Which one will you be using on your project?
Why we should parallel the D.G.sets for power generation? Any presentation on E.G.C.P.( woodward) for parallel
There are a few Woodward EGCP models around. Which one will you be using on your project?
C++, unsure if setting values correctly, and if inheritance is being used correctly?
Here's the code I have so far. I figure my professor wants me to set the values to make the private data accessible. The setFields() method is giving me errors but I'm not sure how to correct it.
#include %26lt;iostream.h%26gt;
class Book
{
private:
title[80]; char author[80]; public:
void setFields();
void displayData();
};
class Fiction:public Book
{
private:
int level;
public:
void getReadingLevel();
void displayReadingLevel();
};
class NonFiction:public Book
{
private:
int numPages;
public:
void getNumPages();
void displayNumPages();
};
void Book::setFields()
{
char t[80], a[80];
title[80]=t[80];
author[80]=a[80];
}
C++, unsure if setting values correctly, and if inheritance is being used correctly?
For one, you don't have a type defined for what the varialbe "table" is. Some C++ compilers allow this, others do not.
What are you trying to accomplish in setFields()? How do you want to data to be accessible?
By the sounds of the problem, and because you're using inheritance, I suspect he wants you to use the 'protected' modifier, rather than public or private. Declaring the variables in the Book base call 'protected' will mean that they will be accessible from all derived classes (i.e. all classes that inherit from Book).
#include %26lt;iostream.h%26gt;
class Book
{
private:
title[80]; char author[80]; public:
void setFields();
void displayData();
};
class Fiction:public Book
{
private:
int level;
public:
void getReadingLevel();
void displayReadingLevel();
};
class NonFiction:public Book
{
private:
int numPages;
public:
void getNumPages();
void displayNumPages();
};
void Book::setFields()
{
char t[80], a[80];
title[80]=t[80];
author[80]=a[80];
}
C++, unsure if setting values correctly, and if inheritance is being used correctly?
For one, you don't have a type defined for what the varialbe "table" is. Some C++ compilers allow this, others do not.
What are you trying to accomplish in setFields()? How do you want to data to be accessible?
By the sounds of the problem, and because you're using inheritance, I suspect he wants you to use the 'protected' modifier, rather than public or private. Declaring the variables in the Book base call 'protected' will mean that they will be accessible from all derived classes (i.e. all classes that inherit from Book).
C++, unsure if setting values correctly, and if inheritance is being used correctly?
Here's the code I have so far. I figure my professor wants me to set the values to make the private data accessible. The setFields() method is giving me errors but I'm not sure how to correct it.
#include %26lt;iostream.h%26gt;
class Book
{
private:
title[80]; char author[80]; public:
void setFields();
void displayData();
};
class Fiction:public Book
{
private:
int level;
public:
void getReadingLevel();
void displayReadingLevel();
};
class NonFiction:public Book
{
private:
int numPages;
public:
void getNumPages();
void displayNumPages();
};
void Book::setFields()
{
char t[80], a[80];
title[80]=t[80];
author[80]=a[80];
}
C++, unsure if setting values correctly, and if inheritance is being used correctly?
Let's say you want to call the setFields() method from outside the Book class, and you want to pass in the values for t and a, which you will assign to the title and author data members. The setFields() method needs to take t and a as parameters like this:
void Book::setFields(char[80] t, char[80]a)
This means that when you call the setFields function, you need to pass it two char arrays for the values of t and a. You won't need this line:
char t[80], a[80]
anymore because those arrays were declared automatically in the first line of the method definition. The rest of what you have in the method is correct.
Reply:insted of inheritance public book try private book
ex
class Fiction:private Book
i hope it works
Reply:you cannot assign array elements to another array using the implementation you are using in the setFields method. you will need to utilize loops to achieve this, good luck.
eg.
for(inti=0;i%26lt;t.size();i++) {title[i] == t[i];}
#include %26lt;iostream.h%26gt;
class Book
{
private:
title[80]; char author[80]; public:
void setFields();
void displayData();
};
class Fiction:public Book
{
private:
int level;
public:
void getReadingLevel();
void displayReadingLevel();
};
class NonFiction:public Book
{
private:
int numPages;
public:
void getNumPages();
void displayNumPages();
};
void Book::setFields()
{
char t[80], a[80];
title[80]=t[80];
author[80]=a[80];
}
C++, unsure if setting values correctly, and if inheritance is being used correctly?
Let's say you want to call the setFields() method from outside the Book class, and you want to pass in the values for t and a, which you will assign to the title and author data members. The setFields() method needs to take t and a as parameters like this:
void Book::setFields(char[80] t, char[80]a)
This means that when you call the setFields function, you need to pass it two char arrays for the values of t and a. You won't need this line:
char t[80], a[80]
anymore because those arrays were declared automatically in the first line of the method definition. The rest of what you have in the method is correct.
Reply:insted of inheritance public book try private book
ex
class Fiction:private Book
i hope it works
Reply:you cannot assign array elements to another array using the implementation you are using in the setFields method. you will need to utilize loops to achieve this, good luck.
eg.
for(inti=0;i%26lt;t.size();i++) {title[i] == t[i];}
What is the risk of moving my C: Program Files folder to D: drive?
I have the Big Fish game manager with a lot of games supported by it. I didn't know this at the time, but when my hard drive started to get too full, I realized that it installs games to C: drive. (I set my exe. files up to go to D: but unbeknownst to me, they install to C). I can't reconfigure this player (Big Fish tech support confirmed this) and my games (about 20 of them, paid for) depend on keeping the player.
Big Fish also told me that while the player sends games to the Program Files folder, it doesn't matter where that folder is.
So theoretically I could move the Program Files folder to D: drive, along with the bulky game downloads...and they would play.
Games are a big part of my computer time, but I don't want to mess around and ruin anything else in the computer by doing this...make other programs unusable or damage them because I do need the computer for other things.
What is the risk of moving my C: Program Files folder to D: drive?
If you move C:\Program Files to D: (should the system let you), I guarantee you'll regret it big time. Lots of things use Program Files (just browse through it and see -- Look but don't touch), and if you move it or rename it, they may not know where to find what they're looking for.
Sorry to disappoint.
Reply:I have run into something similar. I went with a 200gig drive and used the included CD to mirror the C:\ to the 200gig as slave. Power down. Unplug it all. Master jumper pins on the 200gig. Put the D:/ back into the cabinet and everything works.
It is important that whatever mirror program you get runs the computer itself, without WIN running the computer. WIN blocks access to the Windows folder.
Reply:dunno what big fish is, assuming its online gaming.
if its online the biggest problem your gunna run into is if the game tried loading flash or something and looks for the app in a local folder (i.e., in your windows folder) and it doesnt find anything. it may just have your reinstall java or flash, but doubt this is the case
if its a local game then i would leave it on C. games and other programs often make calls to other apps on the computer, and it almost always defaults to look on C for what it needs
Reply:You could loose all that is stored in both
magnolia
Big Fish also told me that while the player sends games to the Program Files folder, it doesn't matter where that folder is.
So theoretically I could move the Program Files folder to D: drive, along with the bulky game downloads...and they would play.
Games are a big part of my computer time, but I don't want to mess around and ruin anything else in the computer by doing this...make other programs unusable or damage them because I do need the computer for other things.
What is the risk of moving my C: Program Files folder to D: drive?
If you move C:\Program Files to D: (should the system let you), I guarantee you'll regret it big time. Lots of things use Program Files (just browse through it and see -- Look but don't touch), and if you move it or rename it, they may not know where to find what they're looking for.
Sorry to disappoint.
Reply:I have run into something similar. I went with a 200gig drive and used the included CD to mirror the C:\ to the 200gig as slave. Power down. Unplug it all. Master jumper pins on the 200gig. Put the D:/ back into the cabinet and everything works.
It is important that whatever mirror program you get runs the computer itself, without WIN running the computer. WIN blocks access to the Windows folder.
Reply:dunno what big fish is, assuming its online gaming.
if its online the biggest problem your gunna run into is if the game tried loading flash or something and looks for the app in a local folder (i.e., in your windows folder) and it doesnt find anything. it may just have your reinstall java or flash, but doubt this is the case
if its a local game then i would leave it on C. games and other programs often make calls to other apps on the computer, and it almost always defaults to look on C for what it needs
Reply:You could loose all that is stored in both
magnolia
Help in C++?
What's the C++ command to:
set the icon
execute a program
Help in C++?
Those are platform (OS) specified functions and are not within the scope of the C++ language. If you are looking for information on how to do it in Windows, check MSDN.
set the icon
execute a program
Help in C++?
Those are platform (OS) specified functions and are not within the scope of the C++ language. If you are looking for information on how to do it in Windows, check MSDN.
Is a/c necessary in San Francisco?
I am moving to San Francisco from the south and I am very spoiled by climate control My a/c is usually set at 65 degrees at night and low 70's/high 60's in the day. I haven't found an apartment with climate control...is it necessary?
Is a/c necessary in San Francisco?
Nope, well it depends on where in the San Francisco Bay Area you are moving to. If you are moving to SF proper or anywhere in the Northbay near the Pacfic ocean than no. If your moving to eastern Alameda or Eastern Contra Costa Counties than definatly. Santa Clara/San Jose area gets really warm too. Anywhere right by the Bay or Ocean, AC is not required. If you live on the opposite side of the hills than 100% u need it.
SF, as a city, is very cool and it only gets to 75-80 degrees on the warmest days of the year. Almost all the other days it is somewhere between 40-65. It is plesant and cool, espcially when the fog moves in. AC can be used, but in SF it is a waste. I live across from the city so yeah.
Reply:Not at all. If anything you'll just need a good heater.
Reply:In the city, its generally mild at night (rarely ever drops below the high 40's) and cool in the day (again, it's rare to see high 80s - 90s), so many apartments don't carry A/C.
However, the natural A/C is really a phenomenon limited to the city center. The issue of climate control becomes a more serious concern if you're staying in the suburbs, where the weather is more typical of California.
Temperatures can become oppressively hot in the summer. It is not uncommon to see almost the entire Bay Area (except for San Francisco and a few coastal communities) top 100 degrees for what seems like forever in July and August.
If you're not looking in SF County or near the water, I would definitely bring up with issue of A/C with the landlord.
Reply:I dunno...I say yes, but that's because I'm a sucker for perfect climate.
Reply:Depending on your comfort range AC may be an issue. I'd be more inclined to get an oxygen tank I could have easy access to, and a mask attached.
You obviously enjoy it chilly, even indoors, though effficiency certainly is compromised in external temp influences on your dwelling.
It does get warm in San Fran.
Rev. Steven
Reply:Not if you are outside.
Reply:NO!! We never use it.
Reply:no. no one has it. A mechanical engineer just ran calculations on a project of mine. In hunters point. among the warmest neighborhoods. and determined that 2 days a year would be to warm... draw the shades or go out and enjoy the weather... If those even happen when your not at work...
Reply:California does have the stereotype of being warm and sunny. The first time I went to San Francisco, the hotel didn't have a/c. I asked the desk clerk what I was suppose to do if I got warm. He told me open a window. I was floored, but he was correct. Generally, it's cool all year around.
Is a/c necessary in San Francisco?
Nope, well it depends on where in the San Francisco Bay Area you are moving to. If you are moving to SF proper or anywhere in the Northbay near the Pacfic ocean than no. If your moving to eastern Alameda or Eastern Contra Costa Counties than definatly. Santa Clara/San Jose area gets really warm too. Anywhere right by the Bay or Ocean, AC is not required. If you live on the opposite side of the hills than 100% u need it.
SF, as a city, is very cool and it only gets to 75-80 degrees on the warmest days of the year. Almost all the other days it is somewhere between 40-65. It is plesant and cool, espcially when the fog moves in. AC can be used, but in SF it is a waste. I live across from the city so yeah.
Reply:Not at all. If anything you'll just need a good heater.
Reply:In the city, its generally mild at night (rarely ever drops below the high 40's) and cool in the day (again, it's rare to see high 80s - 90s), so many apartments don't carry A/C.
However, the natural A/C is really a phenomenon limited to the city center. The issue of climate control becomes a more serious concern if you're staying in the suburbs, where the weather is more typical of California.
Temperatures can become oppressively hot in the summer. It is not uncommon to see almost the entire Bay Area (except for San Francisco and a few coastal communities) top 100 degrees for what seems like forever in July and August.
If you're not looking in SF County or near the water, I would definitely bring up with issue of A/C with the landlord.
Reply:I dunno...I say yes, but that's because I'm a sucker for perfect climate.
Reply:Depending on your comfort range AC may be an issue. I'd be more inclined to get an oxygen tank I could have easy access to, and a mask attached.
You obviously enjoy it chilly, even indoors, though effficiency certainly is compromised in external temp influences on your dwelling.
It does get warm in San Fran.
Rev. Steven
Reply:Not if you are outside.
Reply:NO!! We never use it.
Reply:no. no one has it. A mechanical engineer just ran calculations on a project of mine. In hunters point. among the warmest neighborhoods. and determined that 2 days a year would be to warm... draw the shades or go out and enjoy the weather... If those even happen when your not at work...
Reply:California does have the stereotype of being warm and sunny. The first time I went to San Francisco, the hotel didn't have a/c. I asked the desk clerk what I was suppose to do if I got warm. He told me open a window. I was floored, but he was correct. Generally, it's cool all year around.
Window A/C out of Window?
Can you use a window A/C and just set it on the floor, or does it really need to be sitting in a window to work properly. Am considering getting one but it wont fit in my window. Thanks.
Window A/C out of Window?
No, it has to be vented outside, an a/c unit is a heat exchanger, for every degree that's taken out of the cool air hot air is released outside. if you were to try and run it inside it would pump cold air out of one side and hot out of the other, due to inefficiencies in the system your room would heat up rather than cool down.
Also they produce water, you'd end up with a wet floor.
Reply:yeah it needs to sit in your window for one good reason...draining.
there are some stores that offer single room air conditioners however that do sit on the floor...but you still have to run some hoses out the window.
Reply:Yes it must be out the window, to draw air and drain .
Reply:They make them all different sizes hon, find one that fits.
Reply:Window a/c must be installed in a window or thru the wall to the outside.. There are many sizes available that will fit most windows.
You need to shop around. Measure your window opening first and start looking.
Portable a/c units are also available that might work. Ask about them when you are shopping.
Reply:air conditioning is about removing heat from one location and disposing of it in a more desirable location, (like outside). condensor coil has to be vented outside or you are spinning your wheels. cool air added to space from the evaporator coil will equal the hot air removed from the condensor. oh and the heat from compressor so actually your living space would be warmer!
yeap, gotta mount her in a window!
Window A/C out of Window?
No, it has to be vented outside, an a/c unit is a heat exchanger, for every degree that's taken out of the cool air hot air is released outside. if you were to try and run it inside it would pump cold air out of one side and hot out of the other, due to inefficiencies in the system your room would heat up rather than cool down.
Also they produce water, you'd end up with a wet floor.
Reply:yeah it needs to sit in your window for one good reason...draining.
there are some stores that offer single room air conditioners however that do sit on the floor...but you still have to run some hoses out the window.
Reply:Yes it must be out the window, to draw air and drain .
Reply:They make them all different sizes hon, find one that fits.
Reply:Window a/c must be installed in a window or thru the wall to the outside.. There are many sizes available that will fit most windows.
You need to shop around. Measure your window opening first and start looking.
Portable a/c units are also available that might work. Ask about them when you are shopping.
Reply:air conditioning is about removing heat from one location and disposing of it in a more desirable location, (like outside). condensor coil has to be vented outside or you are spinning your wheels. cool air added to space from the evaporator coil will equal the hot air removed from the condensor. oh and the heat from compressor so actually your living space would be warmer!
yeap, gotta mount her in a window!
Consider eqn of the form x^2 + bx + c = 0. The number of such ...?
equations that have real roots and have coefficients b and c in the set {1,2,3,4,5,6}, (b may be equals to c), is
A) 20;
B) 18;
C) 17;
D) 19;
Please explain, Thanks...
Consider eqn of the form x^2 + bx + c = 0. The number of such ...?
6 ways to choose b
6 ways to choose c
36 possible ways to choose b and c (note that not all of them will have real roots)
For the equation to have real roots: b²≥4c
For b=1: no real roots
For b=2: c = 1
For b=3: c = {1, 2}
For b=4: c = {1, 2, 3, 4}
For b=5: c = {1, 2, 3, 4, 5, 6}
For b=6: c = {1, 2, 3, 4, 5, 6}
Number of possible equations = 1×0 + 1×1 + 1×2 + 1×4 + 1×6 + 1×6 = 19
D
Reply:Real roots if Delta%26gt;=0
ie b^2 -4c %26gt;=0
b^2 %26gt;=4c
List the possibilities
b=1
no values of c
b=2, c=1
b=3, c=1,2,
b=4, c=1,2,3,4
b=5, c=1,2,3,4,5,6
b=6, c=1,2,3,4,5,6
So 19 possibilities
c=1
forsythia
A) 20;
B) 18;
C) 17;
D) 19;
Please explain, Thanks...
Consider eqn of the form x^2 + bx + c = 0. The number of such ...?
6 ways to choose b
6 ways to choose c
36 possible ways to choose b and c (note that not all of them will have real roots)
For the equation to have real roots: b²≥4c
For b=1: no real roots
For b=2: c = 1
For b=3: c = {1, 2}
For b=4: c = {1, 2, 3, 4}
For b=5: c = {1, 2, 3, 4, 5, 6}
For b=6: c = {1, 2, 3, 4, 5, 6}
Number of possible equations = 1×0 + 1×1 + 1×2 + 1×4 + 1×6 + 1×6 = 19
D
Reply:Real roots if Delta%26gt;=0
ie b^2 -4c %26gt;=0
b^2 %26gt;=4c
List the possibilities
b=1
no values of c
b=2, c=1
b=3, c=1,2,
b=4, c=1,2,3,4
b=5, c=1,2,3,4,5,6
b=6, c=1,2,3,4,5,6
So 19 possibilities
c=1
forsythia
Let f: R^+ maps to C^x be the map F(x)=e^ix. prove f is homomorphism & determine its kernal and image?
R is the set of all real numbers. the + means its closed under addition or its an addivitive group.
C is the set of complex numbers. x implies multiplication group. or closed under multiplication.
Let f: R^+ maps to C^x be the map F(x)=e^ix. prove f is homomorphism %26amp; determine its kernal and image?
F(x+y) = e^[i(x+y)] = e^(ix+iy) = (e^ix)(e^iy) = F(x)F(y), and thus
F is a homom.
Since |e^ix| = |cosx + isin x| = cos^2(x) + sin^2(x) = 1, the image of F is S^1 = the multiplicative sbgp. of C* of all complex numbers with module equal to 1.
Now, F(x) = 1 %26lt;==%26gt; e^ix = 1 %26lt;==%26gt; x = 2*Pi*k, with k an integer and Pi = 3.14159.... so:
Ker(F) = {2*Pi*k ; k an integer }
Regards
Tonio
C is the set of complex numbers. x implies multiplication group. or closed under multiplication.
Let f: R^+ maps to C^x be the map F(x)=e^ix. prove f is homomorphism %26amp; determine its kernal and image?
F(x+y) = e^[i(x+y)] = e^(ix+iy) = (e^ix)(e^iy) = F(x)F(y), and thus
F is a homom.
Since |e^ix| = |cosx + isin x| = cos^2(x) + sin^2(x) = 1, the image of F is S^1 = the multiplicative sbgp. of C* of all complex numbers with module equal to 1.
Now, F(x) = 1 %26lt;==%26gt; e^ix = 1 %26lt;==%26gt; x = 2*Pi*k, with k an integer and Pi = 3.14159.... so:
Ker(F) = {2*Pi*k ; k an integer }
Regards
Tonio
I live in s.c. its 107degrees,my a/c has not shut off,is this normal?
I have a 28X68 mobile home, with central a/c and its set at 70 degrees. it didnt shut off until 10pm last night. I change the filters regular.
I live in s.c. its 107degrees,my a/c has not shut off,is this normal?
Yes, that's normal. I am here in georgia, have the ac on 78 and it runs all day before shutting off
Reply:Most A/C systems are designed for a 20-25 degree difference in temperature. If it is 100 degrees outside and inside is 75 degrees it's doing the job. Yes, its normal.
Reply:There isn't an ac made that was designed to maintain 70deg in the summer. You need to get use to a higher setting. Keep raising the thermostat until it cycles once and a while.
Reply:At 107 degrees on a mobile home and with any humidity , it would not be unusal for your a/c to run well past midnight, you might want to clean the evapartor and condenser for maxium efficiency though.
Also make sure that your condensate drain line is not blocked by mold or algae.
Just remember its like your fridge keep the doors closed as much as possible that will help a lot at that temp.
Reply:First off
70 is to darn cold to be keeping your house in summer. Actually 70 is borderline freezing up your AC anyway. you should be running a coil temp above 40 F if the room is 70 and you have a 25degree temp drop the air coming out of your coil is 45 degrees which puts your coil about 35-38 ...thats too close to freezing . ANY problems will cause the coil to freeeze up and stop cooling alltogether. ALSO PLEASE
NOTE: Setting the thermostat to a colder temp will NOT make the AC cool more. It only lowers the temp the AC cuts off at. If your rooom starts off at 90 and you want to get to 78 setting at 78 will do it as fast as setting it at 70. the Temps below 70 are for HEATING not cooling. I advise people to set cooling temps at 78 and heating temps at 68
100 degrees out side you should be around 78 in the house . other wise it can make you sick..
NOW back to the question
YES its normal. Mobile homes are notorious for being hard to cool , not to mention many installers undersize the AC units. OR at leas sized it for more normal temps there.
when the temps outside get over 100 its harder on teh AC to do its job to begin with, and also the heat load on the house goes up. So you have 2 limiting factors on it.
To save some money try setting it to 78 and run a fan. also you can get a water hose and wash out the coils on the outside part of your AC . that is what condenses the freon back to a liquid and removes the heat from your house in the process. If that coil is dirty its less efficient and the AC has to work harder.
Reply:A properly sized AC unit should run almost continuously on the hottest day of the year to keep the inside at a comfortable temperature. If it is only running part time on the hottest day of the year, then it won't be running enough on cooler days to properly dehumidify your home. Of course if it is running full time on the hottest day of the year and you still aren't comfortable then there is a problem.
Reply:I have the same problem with my mobile home in California's Central Valley. It is normal. And be glad you don't live in Blythe, CA. It was 127 when I was there.
Reply:Unfortunately, I live in SC too and I am also dealing with this outrageous heat. My A/C is working overtime too. Best thing you can do is cut down on oven usage and long hot showers because they heat up the house and don't leave the door open long when going in and out.
Reply:Its 107 here also in Alabama. My ac has not shut off because
it is thermostat controlled. That means that it much reach, consistantly cool, and maintain a temperature of say, 78. Because it is so much warmer outside, It must work much harder to reach and keep that temp throughout. So it is staying on much longer than normal.
I live in s.c. its 107degrees,my a/c has not shut off,is this normal?
Yes, that's normal. I am here in georgia, have the ac on 78 and it runs all day before shutting off
Reply:Most A/C systems are designed for a 20-25 degree difference in temperature. If it is 100 degrees outside and inside is 75 degrees it's doing the job. Yes, its normal.
Reply:There isn't an ac made that was designed to maintain 70deg in the summer. You need to get use to a higher setting. Keep raising the thermostat until it cycles once and a while.
Reply:At 107 degrees on a mobile home and with any humidity , it would not be unusal for your a/c to run well past midnight, you might want to clean the evapartor and condenser for maxium efficiency though.
Also make sure that your condensate drain line is not blocked by mold or algae.
Just remember its like your fridge keep the doors closed as much as possible that will help a lot at that temp.
Reply:First off
70 is to darn cold to be keeping your house in summer. Actually 70 is borderline freezing up your AC anyway. you should be running a coil temp above 40 F if the room is 70 and you have a 25degree temp drop the air coming out of your coil is 45 degrees which puts your coil about 35-38 ...thats too close to freezing . ANY problems will cause the coil to freeeze up and stop cooling alltogether. ALSO PLEASE
NOTE: Setting the thermostat to a colder temp will NOT make the AC cool more. It only lowers the temp the AC cuts off at. If your rooom starts off at 90 and you want to get to 78 setting at 78 will do it as fast as setting it at 70. the Temps below 70 are for HEATING not cooling. I advise people to set cooling temps at 78 and heating temps at 68
100 degrees out side you should be around 78 in the house . other wise it can make you sick..
NOW back to the question
YES its normal. Mobile homes are notorious for being hard to cool , not to mention many installers undersize the AC units. OR at leas sized it for more normal temps there.
when the temps outside get over 100 its harder on teh AC to do its job to begin with, and also the heat load on the house goes up. So you have 2 limiting factors on it.
To save some money try setting it to 78 and run a fan. also you can get a water hose and wash out the coils on the outside part of your AC . that is what condenses the freon back to a liquid and removes the heat from your house in the process. If that coil is dirty its less efficient and the AC has to work harder.
Reply:A properly sized AC unit should run almost continuously on the hottest day of the year to keep the inside at a comfortable temperature. If it is only running part time on the hottest day of the year, then it won't be running enough on cooler days to properly dehumidify your home. Of course if it is running full time on the hottest day of the year and you still aren't comfortable then there is a problem.
Reply:I have the same problem with my mobile home in California's Central Valley. It is normal. And be glad you don't live in Blythe, CA. It was 127 when I was there.
Reply:Unfortunately, I live in SC too and I am also dealing with this outrageous heat. My A/C is working overtime too. Best thing you can do is cut down on oven usage and long hot showers because they heat up the house and don't leave the door open long when going in and out.
Reply:Its 107 here also in Alabama. My ac has not shut off because
it is thermostat controlled. That means that it much reach, consistantly cool, and maintain a temperature of say, 78. Because it is so much warmer outside, It must work much harder to reach and keep that temp throughout. So it is staying on much longer than normal.
C drive defragmentation?
Now that I know what it is I'm not sure why mine won't. My C drive is set for defrag every Sunday aat 1:30 am. The problem is it never does. It will go for hours with that paper transfering folders symbol and always stay at 0% complete. Why is this?
C drive defragmentation?
A couple things about defrag.
#1 you need 20-25% free space for the machine to do the defrag. If you don't have the free space, defrag will do more harm than good.
#2 you need to run checkdisk before you do defrag. You should be able to look up check disk in windows help and learn how to do it, if you need help just click on my picture and email me. Be sure to remind me who you are and what you're trying to do as I get lots of email...
Reply:The speed of defrag varies widely. Usually it should be done within a couple of hours. But may take longer for high capacity drives. Before you defrag ensure that there are absolutely *NO* processes running in the background. Including Antivirus %26amp; Firewall software. The defrag process will *STOP* if any software interrupts the defrag program by trying to change the contents of the disk.
Better still, boot your computer in safe mode (Hit F8 continuously while your PC boots and select "Safe Mode" from the boot menu that appears) and defrag now. The safe mode ensures that most background programs are not run in the first place. Hence the defrag can go on without hassles.
If the speed is pathetic still, Try using some third party tool and see if that helps. Eg: Perferct Disk, Mst Defrag (www.mstsoftware.com), Norton's Speed Disk etc. Most of these are commerical software but a sharware version may be available.
Reply:Most of the time defrag wont go, is other items refresing or running in the background..so if it wont defrag normally , start your PC in safemode..F8 when booting...then go into defrag..it should complete it then with no problems.
C drive defragmentation?
A couple things about defrag.
#1 you need 20-25% free space for the machine to do the defrag. If you don't have the free space, defrag will do more harm than good.
#2 you need to run checkdisk before you do defrag. You should be able to look up check disk in windows help and learn how to do it, if you need help just click on my picture and email me. Be sure to remind me who you are and what you're trying to do as I get lots of email...
Reply:The speed of defrag varies widely. Usually it should be done within a couple of hours. But may take longer for high capacity drives. Before you defrag ensure that there are absolutely *NO* processes running in the background. Including Antivirus %26amp; Firewall software. The defrag process will *STOP* if any software interrupts the defrag program by trying to change the contents of the disk.
Better still, boot your computer in safe mode (Hit F8 continuously while your PC boots and select "Safe Mode" from the boot menu that appears) and defrag now. The safe mode ensures that most background programs are not run in the first place. Hence the defrag can go on without hassles.
If the speed is pathetic still, Try using some third party tool and see if that helps. Eg: Perferct Disk, Mst Defrag (www.mstsoftware.com), Norton's Speed Disk etc. Most of these are commerical software but a sharware version may be available.
Reply:Most of the time defrag wont go, is other items refresing or running in the background..so if it wont defrag normally , start your PC in safemode..F8 when booting...then go into defrag..it should complete it then with no problems.
!dea Vs Samsung C-110?
My brother is using my old Samsung C-110 mobile set. He is using !dea SIM which got free with my new Nokia 6030 Phone. Problem is that whenever he receives a call, the cell will get restarted automatically before completing the call. He replaced that 16K Sim with 32 K. Now the frequecy of the problem reduced, but still can't predict when this problem will happen.
We tested by interchanging our phones and SIMs. Now the problamatic !dea SIM is working fine with Nokia 6030 cell!
Dears, how to make !dea SIM to work with Samsung C-100?
Please don't suggest me to give my phone to him!
!dea Vs Samsung C-110?
threz smthing wrng wid ur bro's phone .,. get it checked out
Reply:Dear, Visit Idea Customer Care service station near your location and the experts sole your problem 100% . Good Luck
jasmine
We tested by interchanging our phones and SIMs. Now the problamatic !dea SIM is working fine with Nokia 6030 cell!
Dears, how to make !dea SIM to work with Samsung C-100?
Please don't suggest me to give my phone to him!
!dea Vs Samsung C-110?
threz smthing wrng wid ur bro's phone .,. get it checked out
Reply:Dear, Visit Idea Customer Care service station near your location and the experts sole your problem 100% . Good Luck
jasmine
What is the solution set of 3x - 2y > 6?
The answer is one of the following
A.) (2 , - 3)
B.) a set of ordered pairs in a plane
C.) the empty set
D.) a boundary line
What is the solution set of 3x - 2y %26gt; 6?
B (any x %26gt; (6+2y)/3 would satisfy the equation)
Reply:The option A indicates that only the points x=2, and y=-3 can satisfy the equation, but any set of coordinates can satisfy the equation. Example: (6,1), (4,0), and so on. There are infinite possibilities that exist.
Therefore, any set of ordered pairs satisfy the equation. Correct Answer is 'B'.
Reply:Aaaaaa,
Says Fonzie
Reply:Noooo it's not A... B is the answer.
Reply:yup
Reply:A!
A.) (2 , - 3)
B.) a set of ordered pairs in a plane
C.) the empty set
D.) a boundary line
What is the solution set of 3x - 2y %26gt; 6?
B (any x %26gt; (6+2y)/3 would satisfy the equation)
Reply:The option A indicates that only the points x=2, and y=-3 can satisfy the equation, but any set of coordinates can satisfy the equation. Example: (6,1), (4,0), and so on. There are infinite possibilities that exist.
Therefore, any set of ordered pairs satisfy the equation. Correct Answer is 'B'.
Reply:Aaaaaa,
Says Fonzie
Reply:Noooo it's not A... B is the answer.
Reply:yup
Reply:A!
One Parabola For Each Value of c?
The equation y = x^2 + c defines a family of parabolas, one parabola for each value of c. On one set of coordinates axes, graph the members of the family for c = 0, c = 3 and c = -2.
One Parabola For Each Value of c?
Let us consider the parabola where c = 0
y = x^2
Let x = -2, -1, 0, 1 and 2.
We find y = 4, 1, 0 ,1 and 4 in that order.
Graph those points and you will get a basic parabola, a U shaped curve. As x continues to move to the right and left the cure should get steeper and steeper. (It does not curve back on itself as does a circle. You can also try substituting -3 and 3 for x.)
Having suggested that approach for y = x^2. You should use the same x values for:
y = x^2 -2 and y =x^2 +3. If you really want to understand this concept I would suggest you go a step further and try y = x^2 +1
Reply:Giving a representation of a graph, let alone a curved graph, on here as an answer is nigh impossible. However, you may see how they look at this website: http://www.calc5.com/#graph(x*x%2C%20x*x...
One Parabola For Each Value of c?
Let us consider the parabola where c = 0
y = x^2
Let x = -2, -1, 0, 1 and 2.
We find y = 4, 1, 0 ,1 and 4 in that order.
Graph those points and you will get a basic parabola, a U shaped curve. As x continues to move to the right and left the cure should get steeper and steeper. (It does not curve back on itself as does a circle. You can also try substituting -3 and 3 for x.)
Having suggested that approach for y = x^2. You should use the same x values for:
y = x^2 -2 and y =x^2 +3. If you really want to understand this concept I would suggest you go a step further and try y = x^2 +1
Reply:Giving a representation of a graph, let alone a curved graph, on here as an answer is nigh impossible. However, you may see how they look at this website: http://www.calc5.com/#graph(x*x%2C%20x*x...
Prove FLT on a single page mathematicaly if a^n=c^2-b^2.for given a and n there are infinite sets of c and b.
if a^n=c^2-b^2
let b=c-a^R,where R is a random constant ranging from -infinity to +infinity.
putting the value of b in the equation we get
c=a^n+a^2R/2a^R %26amp; b=a^n-a^2R/2a^R.
putting n=2 %26amp; a as 3 and selecting R as 2 we get the famous equation
3^2+4^2=5^2.here selection of R must be done very carefully and as it ranges from -infinity to +infinity there are infinitely many solutions of c and b for a given a and n.
by giving a few more treatments to the above formula and by proving that there lies a common factor between a,b and c when a=b+c sir fermats last theorem can be proved very easily mathematically on a single sided page.
Prove FLT on a single page mathematicaly if a^n=c^2-b^2.for given a and n there are infinite sets of c and b.
you arguments are good, however i swear that proving FLT isn't so easy . the best will that you yourself prove FLT in a single page checking out every arguments.
after all it took 350 yrs to find a proof !!
keep on trying ,good luck.
Reply:I take it FLT is Fermat's Last Theorem, not a Falafel, Lettuce and Tomato sandwich?
Reply:Could you put parenthesis around which letters are receiving the "^" symbol? I'm not sure where to assume they go...
let b=c-a^R,where R is a random constant ranging from -infinity to +infinity.
putting the value of b in the equation we get
c=a^n+a^2R/2a^R %26amp; b=a^n-a^2R/2a^R.
putting n=2 %26amp; a as 3 and selecting R as 2 we get the famous equation
3^2+4^2=5^2.here selection of R must be done very carefully and as it ranges from -infinity to +infinity there are infinitely many solutions of c and b for a given a and n.
by giving a few more treatments to the above formula and by proving that there lies a common factor between a,b and c when a=b+c sir fermats last theorem can be proved very easily mathematically on a single sided page.
Prove FLT on a single page mathematicaly if a^n=c^2-b^2.for given a and n there are infinite sets of c and b.
you arguments are good, however i swear that proving FLT isn't so easy . the best will that you yourself prove FLT in a single page checking out every arguments.
after all it took 350 yrs to find a proof !!
keep on trying ,good luck.
Reply:I take it FLT is Fermat's Last Theorem, not a Falafel, Lettuce and Tomato sandwich?
Reply:Could you put parenthesis around which letters are receiving the "^" symbol? I'm not sure where to assume they go...
Show by computing derivatives, that sin^2x=-1/2cos2x+c for some constant c. Find c by setting x=0?
I'm a little lost on how to approach this problem. Any help would be appreciated, thanks guys
Show by computing derivatives, that sin^2x=-1/2cos2x+c for some constant c. Find c by setting x=0?
Define function f(x)= sin^2(x)+ 1/2*cos(2x)
Compute its derivative
f'(x)=2sin(x)*cos(x) - 1/2*2*sin(2x) by the Power Rule/Chain Rule
Simplify f'(x) using trig identity sin(2x)=2sin(x)cos(x)
You get f'(x)=0
So f(x)=c for some constant c.
Since f(x) is constant it has the same value c for any x.
So f(0)=sin^2(x)+ 1/2*cos(0) =1/2 = c
crab apple
Show by computing derivatives, that sin^2x=-1/2cos2x+c for some constant c. Find c by setting x=0?
Define function f(x)= sin^2(x)+ 1/2*cos(2x)
Compute its derivative
f'(x)=2sin(x)*cos(x) - 1/2*2*sin(2x) by the Power Rule/Chain Rule
Simplify f'(x) using trig identity sin(2x)=2sin(x)cos(x)
You get f'(x)=0
So f(x)=c for some constant c.
Since f(x) is constant it has the same value c for any x.
So f(0)=sin^2(x)+ 1/2*cos(0) =1/2 = c
crab apple
I'm having the same problem as Charles C - problems setting up the Touch on my home router (WRT54G).?
Once entered, the device sees the SSID, indicates good signal strength, but Safari and iTunes Store return "cannot find server" when trying to connect. I have triple and quadruple-checked the password (for WPA encryption), ensured that DCHP is enabled. Not sure which IP/Subnet and DNS (if required?) to enter on the Touch from my router's status page. I will try temporarily removing security tonight to see if that helps. If anyone has other suggestions, I would appreciate it!
I'm having the same problem as Charles C - problems setting up the Touch on my home router (WRT54G).?
Well if you have a good strength and the password correct it still doesn't mean that you have internet access, it just means that you have a good connection from your computer to the wireless router. I will suggest to restore your router to default by pressing the reset button. Try first by doing it with no security at all, then when it works you should put the encryption.
After you restored your router, go to your computer and go to control panel - Network connection - right click your wireless connection icon - then select properties. The select TCP/IP and click on properties again. Make sure that is set for windows to choose your IP address.
After you have done that use any of your web browser to check if you have internet connection. It seems that you are using a Apple computer if i'm not mistaken since you are using Safari (Of course it doesn't mean that you cannot have safari in a PC) Anyways, another problem that you might have is the type of internet service that you have. Do you have DSL or Cable or something else????
If you have a broadband service it is for sure that the internet company have installed a modem in your house, Now days those modems comes with routing capabilities. If that is the case that modem might be doing DHCP and by default your linksys router does DHCP too so they would conflict with the IP addresses and no computer will know what IP address is assigned to them, so write me back telling me what kind of internet service you have and what brand and model is your modem.
I'm having the same problem as Charles C - problems setting up the Touch on my home router (WRT54G).?
Well if you have a good strength and the password correct it still doesn't mean that you have internet access, it just means that you have a good connection from your computer to the wireless router. I will suggest to restore your router to default by pressing the reset button. Try first by doing it with no security at all, then when it works you should put the encryption.
After you restored your router, go to your computer and go to control panel - Network connection - right click your wireless connection icon - then select properties. The select TCP/IP and click on properties again. Make sure that is set for windows to choose your IP address.
After you have done that use any of your web browser to check if you have internet connection. It seems that you are using a Apple computer if i'm not mistaken since you are using Safari (Of course it doesn't mean that you cannot have safari in a PC) Anyways, another problem that you might have is the type of internet service that you have. Do you have DSL or Cable or something else????
If you have a broadband service it is for sure that the internet company have installed a modem in your house, Now days those modems comes with routing capabilities. If that is the case that modem might be doing DHCP and by default your linksys router does DHCP too so they would conflict with the IP addresses and no computer will know what IP address is assigned to them, so write me back telling me what kind of internet service you have and what brand and model is your modem.
In C:drive-documents and setting-i want to change the name of my folder how can i do that?
Iam using xp, in that c:drive-documents and setting there are 3 folders 1. administrator, 2.all users and name of my folder but i want to change the name of this folder.
When I rename it, mge appears we cannot change because it is sharing folder. But I have to change the name so badly.Is any one is there to help please.
In C:drive-documents and setting-i want to change the name of my folder how can i do that?
You really can't rename the folder without causing major issues. The folder needs to retain the name in order for that account to work properly. The easiest way to have a folder name of your choice in that directory is to have your computer administrator A) change your user-name (the folder will be renamed according to your user-name) or B) make a new account with the desired user-name. If you are the administrator of your computer then trying to change the name of the account first created is quite hard and trick A will not work, but B should work just fine (you'll need to transfer your "My Documents" folder if you want to keep your files). To clarify, when I mean the administrator of the computer I am referring to the person who first set up the computer plus its accounts and who had the first account. If you have administrator privileges and your are not the original account holder then both tricks should work.
Reply:I think it's because the folder name is based on your sign-in name for XP (like what you click to get onto your home screen, if that makes any sense.) I think that changing that name is the only way to change the name of your documents and settings folder. To do that you go to Control Panel %26gt; User Accounts %26gt; Change An Account %26gt; (your account) %26gt; Change My Name. I've not tested this method but it hypothetically should work. Hope this helps!
Reply:go to properties %26gt; sharing %26gt; and un-check share this folder
click apply and rename. it should work but WinXP might have a block on that folder. try it out!
Reply:I don't know if I can help you. In windows xp, if you rename a restricted folder windows needs in that directory, it will simply create a new folder replace the one you renamed.
Do you have it shared across the network? That shouldn't stop you from changing, just a warning message. Folder properties should tell you that much and allow you to disable it.
Nothing else comes to mind. Just remember that windows needs one folder corresponding to each user in that directory.
Reply:Dear,
it is the folder that which is using as system folder.
so if you want to change it. first login as administrator and delete the exitsing uers. creat as you want. this is inly the way...Try it...! Enjoy.
Reply:You can't rename it. If you must, you must change the name of the account that corresponds to that folder. To do that, press Start then Control Panel. Then click on User Accounts and User Accounts again. (In category View, for Classic, just click on User Accounts) Then click on the account that corresponds with the folder that you want to change the name. Click on that account and click on Change the name. Type in the name you want and click on Apply or OK. This should change the name of the folder under the directory of: C:\Documents and Settings.
Reply:Just right-click on the folder and scroll down to "rename". Just type in the name you want.
Hope that helps.
Oops. Just looked again. You are trying to change the name of a system file. Can't be done...sorry.
When I rename it, mge appears we cannot change because it is sharing folder. But I have to change the name so badly.Is any one is there to help please.
In C:drive-documents and setting-i want to change the name of my folder how can i do that?
You really can't rename the folder without causing major issues. The folder needs to retain the name in order for that account to work properly. The easiest way to have a folder name of your choice in that directory is to have your computer administrator A) change your user-name (the folder will be renamed according to your user-name) or B) make a new account with the desired user-name. If you are the administrator of your computer then trying to change the name of the account first created is quite hard and trick A will not work, but B should work just fine (you'll need to transfer your "My Documents" folder if you want to keep your files). To clarify, when I mean the administrator of the computer I am referring to the person who first set up the computer plus its accounts and who had the first account. If you have administrator privileges and your are not the original account holder then both tricks should work.
Reply:I think it's because the folder name is based on your sign-in name for XP (like what you click to get onto your home screen, if that makes any sense.) I think that changing that name is the only way to change the name of your documents and settings folder. To do that you go to Control Panel %26gt; User Accounts %26gt; Change An Account %26gt; (your account) %26gt; Change My Name. I've not tested this method but it hypothetically should work. Hope this helps!
Reply:go to properties %26gt; sharing %26gt; and un-check share this folder
click apply and rename. it should work but WinXP might have a block on that folder. try it out!
Reply:I don't know if I can help you. In windows xp, if you rename a restricted folder windows needs in that directory, it will simply create a new folder replace the one you renamed.
Do you have it shared across the network? That shouldn't stop you from changing, just a warning message. Folder properties should tell you that much and allow you to disable it.
Nothing else comes to mind. Just remember that windows needs one folder corresponding to each user in that directory.
Reply:Dear,
it is the folder that which is using as system folder.
so if you want to change it. first login as administrator and delete the exitsing uers. creat as you want. this is inly the way...Try it...! Enjoy.
Reply:You can't rename it. If you must, you must change the name of the account that corresponds to that folder. To do that, press Start then Control Panel. Then click on User Accounts and User Accounts again. (In category View, for Classic, just click on User Accounts) Then click on the account that corresponds with the folder that you want to change the name. Click on that account and click on Change the name. Type in the name you want and click on Apply or OK. This should change the name of the folder under the directory of: C:\Documents and Settings.
Reply:Just right-click on the folder and scroll down to "rename". Just type in the name you want.
Hope that helps.
Oops. Just looked again. You are trying to change the name of a system file. Can't be done...sorry.
I have minicam 100k digi camera,put c.d in wat came with it.every think works exceptwen.i download says no cam
i have minicam100k digi camera,have set up c.d softwere which came with it,every think works except wen i go to download pic of camera,it says no camera found,some 1 told me could need new driver?
I have minicam 100k digi camera,put c.d in wat came with it.every think works exceptwen.i download says no cam
Try re-installing the USB cable driver. Or try using a different USB port on your computer.
I have minicam 100k digi camera,put c.d in wat came with it.every think works exceptwen.i download says no cam
Try re-installing the USB cable driver. Or try using a different USB port on your computer.
Let A, B, and C be sets, and let f:AarrowB and g:BarrowC be funtions. Prove or dis prove each of the following
If the composite function g o f: AarrowC is a surjection, then the function f:AarrowB is a surjection.
If the composite function g o f:AarrowC is a surjection, then the function g:BarrowC is a surjection.
Let A, B, and C be sets, and let f:AarrowB and g:BarrowC be funtions. Prove or dis prove each of the following
Let A = B = all non negative integers (it includes 0, although this does not matter).
Let C be the set {0,1}
f(a) = a - 10*INT(a/10)
in words: f(a) is the remainder when a s divided by 10.
if a is written in base 10, then f(a) is the lst digit.
example a = 734, then f(a) = 4
g(b) = b - 2*INT(b/2)
in words: f(b) is the remainder when b is divided by 2.
if b is even, g(b)=0; if b is odd, g(b)=1
Both functions are well-defined.
f:A--%26gt;B is not surjective,
yet g o f:A---%26gt;C is surjective.
-----
To prove the second one, I'd try to prove that g is not surjective even though g o f is surjective. This will lead to a contradiction.
strawberry
If the composite function g o f:AarrowC is a surjection, then the function g:BarrowC is a surjection.
Let A, B, and C be sets, and let f:AarrowB and g:BarrowC be funtions. Prove or dis prove each of the following
Let A = B = all non negative integers (it includes 0, although this does not matter).
Let C be the set {0,1}
f(a) = a - 10*INT(a/10)
in words: f(a) is the remainder when a s divided by 10.
if a is written in base 10, then f(a) is the lst digit.
example a = 734, then f(a) = 4
g(b) = b - 2*INT(b/2)
in words: f(b) is the remainder when b is divided by 2.
if b is even, g(b)=0; if b is odd, g(b)=1
Both functions are well-defined.
f:A--%26gt;B is not surjective,
yet g o f:A---%26gt;C is surjective.
-----
To prove the second one, I'd try to prove that g is not surjective even though g o f is surjective. This will lead to a contradiction.
strawberry
Let A, B, C be sets. Prove that if A is a subset of B and B is a subset of C, then A is a subset of C.?
all the elements found in set A are found in set B if all the elements found in set B are found in set C therefore all the elements in set A which is a subset of set B are found in set C scince set B is a subset of of C
Let A, B, C be sets. Prove that if A is a subset of B and B is a subset of C, then A is a subset of C.?
B is a subset of C (B is included in C)
A is a subset of B (A is included in B)
If B is included in C, and A in B, then A is included in C
Reply:Using Venn diagram draw three loops loop represents set A inside loop represents set B which is in side loop represents set C ,then A inside C ,then A is subset of C.
Let A, B, C be sets. Prove that if A is a subset of B and B is a subset of C, then A is a subset of C.?
B is a subset of C (B is included in C)
A is a subset of B (A is included in B)
If B is included in C, and A in B, then A is included in C
Reply:Using Venn diagram draw three loops loop represents set A inside loop represents set B which is in side loop represents set C ,then A inside C ,then A is subset of C.
Subtracting sets? What does something like [A and (B - C)] mean, where A, B, C are sets?
A, B, and C are sets.
A has yellow, purple, and blue.
B has yellow, green, and black.
C has green, orange, and brown.
The union of A and B is yellow, purple, green, blue, and black. That's the total of everything in A and B.
The intersection of A and B is yellow.
That's what A and B has in common.
Suppose we have B - C.
B has yellow, green, and black.
C has green, orange, and brown.
B - C is {yellow, green, black} - {green, orange, brown}.
What do B and C have in common? Green.
Thus,
B - C is {yellow, green, black} - {green}.
Now, B - C = {yellow, black}.
All I did was that I took away the green.
Orange and brown has no effect on B because B doesn't have orange and brown.
Subtracting sets? What does something like [A and (B - C)] mean, where A, B, C are sets?
The difference of sets, like B - C usually means in B, but not in C.
If D = B-C, the A and D usually means the intersection of A and D, or, in both A and D.
Reply:B - C is the set of all ements in B that are NOT in C
A and B-C is their interaction, the set of elements that's in both A and B-C
Reply:that means you find first the relative complement of C with respect to B. and you find the intersection of the resulting set to set A.
relative complement of C wrt B are the elements of set B not in set C
A has yellow, purple, and blue.
B has yellow, green, and black.
C has green, orange, and brown.
The union of A and B is yellow, purple, green, blue, and black. That's the total of everything in A and B.
The intersection of A and B is yellow.
That's what A and B has in common.
Suppose we have B - C.
B has yellow, green, and black.
C has green, orange, and brown.
B - C is {yellow, green, black} - {green, orange, brown}.
What do B and C have in common? Green.
Thus,
B - C is {yellow, green, black} - {green}.
Now, B - C = {yellow, black}.
All I did was that I took away the green.
Orange and brown has no effect on B because B doesn't have orange and brown.
Subtracting sets? What does something like [A and (B - C)] mean, where A, B, C are sets?
The difference of sets, like B - C usually means in B, but not in C.
If D = B-C, the A and D usually means the intersection of A and D, or, in both A and D.
Reply:B - C is the set of all ements in B that are NOT in C
A and B-C is their interaction, the set of elements that's in both A and B-C
Reply:that means you find first the relative complement of C with respect to B. and you find the intersection of the resulting set to set A.
relative complement of C wrt B are the elements of set B not in set C
How can I change the setting of Hard drive (e.g. C) to 'open' by default when it is double clicked?
The default setting of my C: and D: drive is changed to be 'autoplay'.
How can I change the setting of Hard drive (e.g. C) to 'open' by default when it is double clicked?
It seems like your computer is infected with the virus.
here is the checklist to insure whether it is infected or not
Go to start %26gt;%26gt; Run%26gt;%26gt;cmd
on the prompt type cd\
you will get the default drive it may be C: or D:
again type attrib
this will display all the attributes of files including hidden files too.
Find the filename autorun.inf over there
type dir *.inf it will show you the all the inf files.
If you find autorun.inf file .Use this command
type autorun.inf
see whether if there is any things like wscript.exe or Ravmon.exe or any application ending with .exe
it is sure that your computer is effected with virus if you find any .exe over there.
If this is not case , your registry settings has been changed.
see if you can delete the autorun.inf file
del autorun.inf
if the above command deletes the autorun.inf file now the autoplay is gone on the drive.
before deleting use this command
attrib -a -r -s -h
and use the command
del autorun.inf
This will fix the autoplay for the Drive . if this doesnot fix, pls mail to me at info@hostyasui.com , I will provide you further support.
How can I change the setting of Hard drive (e.g. C) to 'open' by default when it is double clicked?
It seems like your computer is infected with the virus.
here is the checklist to insure whether it is infected or not
Go to start %26gt;%26gt; Run%26gt;%26gt;cmd
on the prompt type cd\
you will get the default drive it may be C: or D:
again type attrib
this will display all the attributes of files including hidden files too.
Find the filename autorun.inf over there
type dir *.inf it will show you the all the inf files.
If you find autorun.inf file .Use this command
type autorun.inf
see whether if there is any things like wscript.exe or Ravmon.exe or any application ending with .exe
it is sure that your computer is effected with virus if you find any .exe over there.
If this is not case , your registry settings has been changed.
see if you can delete the autorun.inf file
del autorun.inf
if the above command deletes the autorun.inf file now the autoplay is gone on the drive.
before deleting use this command
attrib -a -r -s -h
and use the command
del autorun.inf
This will fix the autoplay for the Drive . if this doesnot fix, pls mail to me at info@hostyasui.com , I will provide you further support.
A-(BuC) = (A-B)n(A-C)?
a,b,c are sets. i know this is true but i'm needing some help coming up with the proof. any ideas or directions are greatly appreciated. thanks
A-(BuC) = (A-B)n(A-C)?
Whenever you're out to show the equivalence of two sets, you need to show that each is a subset of the other. So in our case, start with showing that A-(BuC) is a subset of (A-B)n(A-C), then vice versa.
To show that a set is a subset of another, we take any element from the first and show that it is also in the second.
So let x be in A-(BuC). Then (by def. of "-") x is in A and x is not in (BuC). Since x is not in BuC, x is not in B and x is not in C. Since x is in A but not B, x is in (A-B). Since x is in A but not in C, x is in (A-C). Since it's in both, it's in the intersection.
This argument shows that the first set is a subset of the second. This argument is nice because you can pretty much reverse its steps in building a proof that the second set is a subset of the first. After you've done this, you're done.
kudzu
A-(BuC) = (A-B)n(A-C)?
Whenever you're out to show the equivalence of two sets, you need to show that each is a subset of the other. So in our case, start with showing that A-(BuC) is a subset of (A-B)n(A-C), then vice versa.
To show that a set is a subset of another, we take any element from the first and show that it is also in the second.
So let x be in A-(BuC). Then (by def. of "-") x is in A and x is not in (BuC). Since x is not in BuC, x is not in B and x is not in C. Since x is in A but not B, x is in (A-B). Since x is in A but not in C, x is in (A-C). Since it's in both, it's in the intersection.
This argument shows that the first set is a subset of the second. This argument is nice because you can pretty much reverse its steps in building a proof that the second set is a subset of the first. After you've done this, you're done.
kudzu
Help with C++ Program ?
Program takes celsius degree
// and converts it to fahrenhite
// in increments of 5
#include %26lt;iostream%26gt;
using std::cout; // program uses cout
using std::cin; // program uses cin
using std::endl; // program uses endl
#include %26lt;iomanip%26gt;
using std::setw;
int main()
{
int c, f, even, odd; // declares variables
cout %26lt;%26lt; "Input data in intervals of 5" %26lt;%26lt; endl;
cout %26lt;%26lt; "Start from 0" %26lt;%26lt; endl;
for (f = 0; f %26lt; 100; f++)
// Counter to loop a hundred times
{
f = f*5;
c = (.5555556)*(f-32);
if( c %26amp; 0x00000001 )
{
c = even;
}
else
c = odd;
cout%26lt;%26lt; setw( 5 ) %26lt;%26lt; "Odd"%26lt;%26lt; setw( 5 ) %26lt;%26lt; "Even" %26lt;%26lt; endl;
cout%26lt;%26lt; setw( 5 ) %26lt;%26lt; odd %26lt;%26lt; setw( 5 ) %26lt;%26lt; even %26lt;%26lt; endl;
// conversion Formula set to c
cout %26lt;%26lt; "The Celsius equivalent is: " %26lt;%26lt; c;
// printout statement
if(c %26lt; 35)
// Checks to see
Help with C++ Program ?
..yikes, what are you trying to do!?
is it a program that takes C, converts it to F, and THEN adds 5 , or is it a program that displays the C temperature in F, in intervals of 5?
the latter sounds more reasonable, I guess...but ONE of your problems is that you are using your loop controls as variables to convert the temp, so after the firs time in your first for loop the variable goes to 6, the second time to 30, and then to 150!! don't use the F variable as loop control if it is for conversion, unless you are going to restore back its value after the conversion, in which case makes no sense...you should just use ANOTHER variable for loop control
Reply:Your temperatures should be floats.
Reply:sorry, i'm not entirely sure about what youre trying to do...
but to convert a temp C to F i would do this
int main (void)
{
double c, f;
cout%26lt;%26lt;"Enter a temperature in degrees Celsius: ";
cin%26gt;%26gt;c;
cout%26lt;%26lt;endl;
f = 9.0/5.0*c + 32;
cout%26lt;%26lt;c%26lt;%26lt;" degrees Celsius is equal to "%26lt;%26lt;f%26lt;%26lt;" degrees Fahrenheit.";
return 0;
}
If you're trying to make a scale of temperatures, something like
0C = 32F
5C = 41F
10C = 50F
15C = 59F
...one hundred times, make a loop that
-changes C to F
-prints value of C and F
-adds 5 to C
something like
double c = 0, f;
for(int loop = 0; loop %26lt; 100; loop++)
{
f = 9.0/5.0*c + 32;
cout%26lt;%26lt;c%26lt;%26lt;"C = "%26lt;%26lt;f%26lt;%26lt;"F"%26lt;%26lt;endl;
c += 5;
}
hope this helps you, good luck with the programming.
// and converts it to fahrenhite
// in increments of 5
#include %26lt;iostream%26gt;
using std::cout; // program uses cout
using std::cin; // program uses cin
using std::endl; // program uses endl
#include %26lt;iomanip%26gt;
using std::setw;
int main()
{
int c, f, even, odd; // declares variables
cout %26lt;%26lt; "Input data in intervals of 5" %26lt;%26lt; endl;
cout %26lt;%26lt; "Start from 0" %26lt;%26lt; endl;
for (f = 0; f %26lt; 100; f++)
// Counter to loop a hundred times
{
f = f*5;
c = (.5555556)*(f-32);
if( c %26amp; 0x00000001 )
{
c = even;
}
else
c = odd;
cout%26lt;%26lt; setw( 5 ) %26lt;%26lt; "Odd"%26lt;%26lt; setw( 5 ) %26lt;%26lt; "Even" %26lt;%26lt; endl;
cout%26lt;%26lt; setw( 5 ) %26lt;%26lt; odd %26lt;%26lt; setw( 5 ) %26lt;%26lt; even %26lt;%26lt; endl;
// conversion Formula set to c
cout %26lt;%26lt; "The Celsius equivalent is: " %26lt;%26lt; c;
// printout statement
if(c %26lt; 35)
// Checks to see
Help with C++ Program ?
..yikes, what are you trying to do!?
is it a program that takes C, converts it to F, and THEN adds 5 , or is it a program that displays the C temperature in F, in intervals of 5?
the latter sounds more reasonable, I guess...but ONE of your problems is that you are using your loop controls as variables to convert the temp, so after the firs time in your first for loop the variable goes to 6, the second time to 30, and then to 150!! don't use the F variable as loop control if it is for conversion, unless you are going to restore back its value after the conversion, in which case makes no sense...you should just use ANOTHER variable for loop control
Reply:Your temperatures should be floats.
Reply:sorry, i'm not entirely sure about what youre trying to do...
but to convert a temp C to F i would do this
int main (void)
{
double c, f;
cout%26lt;%26lt;"Enter a temperature in degrees Celsius: ";
cin%26gt;%26gt;c;
cout%26lt;%26lt;endl;
f = 9.0/5.0*c + 32;
cout%26lt;%26lt;c%26lt;%26lt;" degrees Celsius is equal to "%26lt;%26lt;f%26lt;%26lt;" degrees Fahrenheit.";
return 0;
}
If you're trying to make a scale of temperatures, something like
0C = 32F
5C = 41F
10C = 50F
15C = 59F
...one hundred times, make a loop that
-changes C to F
-prints value of C and F
-adds 5 to C
something like
double c = 0, f;
for(int loop = 0; loop %26lt; 100; loop++)
{
f = 9.0/5.0*c + 32;
cout%26lt;%26lt;c%26lt;%26lt;"C = "%26lt;%26lt;f%26lt;%26lt;"F"%26lt;%26lt;endl;
c += 5;
}
hope this helps you, good luck with the programming.
Need help with c- programming?
A few problems i need help with...
1. I have to have the user clear scores before entering the first set of test scores because the test score number starts of in the millions.
2. I can't get the program to enter a second set of numbers after the first set has been cleared.
3. How to get the program to count the sets as i enter them in. ( I will be saving them in a file)
#include %26lt;stdio.h%26gt;
#include %26lt;stdlib.h%26gt;
#include %26lt;math.h%26gt;
int main()
{
int eLoop=0,bsinp;
char menuResponse;
float score;
float average;
float x;
float max = 0;
float min = 1000;
float total = 0;
float sum;
int i = 0;
char buffer[BUFSIZ+1];
int scoresEntered;
int setsEntered;
do{
/*Print the Menu*/
printf ( "\n\n\**********************************...
printf ("*****Test Score Statisics v2.0*****\n");
printf ("***********************************\n"...
printf ("[C] Clear Stats\n");
printf ("[E] Enter Test Scores\n");
printf ("[D] Display Test Score Stats\n");
printf ("[Q] Quit\n\n");
printf ("Type the letter of your selection and press %26lt;ENTER%26gt;\n");
gets(buffer);
menuResponse = buffer[0];
switch (menuResponse)
{
/*Clear all scores and tally the total sets*/
case 'C':
case 'c':
printf("All Scores Cleared.\n");
setsEntered++;
max = 0;
min = 100;
int i = 0;
float total = 0;
break;
case 'E':
case 'e':
while ( score ) {
printf("Please Enter test Score %d: ", i+1);
score = atoi(gets(buffer));
i = i + 1;
if (buffer[0] == 0) break;
if( score %26gt; max ) { /* Find Max Score*/
max = score;
}else{
if (score %26lt; min) { /* Find Min Score*/
min = score;
}
}
sum = score + sum; /* Find Sum Score*/
}
average = sum / (i-1) ; /* Find Average Score*/
break;
case 'D':
case 'd':
printf( "\n\nThe average score is %.1f\n", average);
printf( "%d Test Scores\n", i-1 );
printf( "Maximun Test Score = %.1f\n", max);
printf( "Minimum Test Score = %.1f\n", min);
printf( "\n\nPlease Clear Scores before preceding.");
break;
case 'Q':
case 'q':
eLoop=1;
break;
default:
printf("Please select a letter.\n");
break;
}
}while (eLoop!=1);
printf("Press Any Key.\n");
gets(bsinp);
return 0;
}
Need help with c- programming?
sorry I'll just have to paste the full code here (commented where necessary). there were a few other flaws as well, also added support for writing sets to file. enjoy.
#include %26lt;stdio.h%26gt;
#include %26lt;stdlib.h%26gt;
#include %26lt;math.h%26gt;
int main()
{
int eLoop=0;
char menuResponse;
float score;
float average=0;
float max = 0;
float min = 0;
float sum=0;
int i = 0;
char buffer[BUFSIZ+1];
int setsEntered;
FILE *fd;
// open file where you put sets
if (NULL == (fd = fopen("mysets.txt", "w")))
{
printf ("\n Sorry couldn't open mysets.txt, change path or give permissions.\n");
exit(1);
}
do
{
/*Print the Menu*/
printf ( "\n\n***********************************...
printf ( "*****Test Score Statisics v2.0*****\n");
printf ( "***********************************\n")...
printf ("[C] Clear Stats\n");
printf ("[E] Enter Test Scores\n");
printf ("[D] Display Test Score Stats\n");
printf ("[Q] Quit\n\n");
printf ("Type the letter of your selection and press %26lt;ENTER%26gt;\n");
gets(buffer);
menuResponse = buffer[0];
switch (menuResponse)
{
/*Clear all scores and tally the total sets*/
case 'C':
case 'c':
printf("All Scores Cleared.\n");
max = 0;
min = 0;
i = 0;
sum = 0;
average = 0;
break;
case 'E':
case 'e':
if (0 != i)
{
printf (" %26lt;%26lt;%26lt; YOU MUST CLEAR PREVIOUS SCORES FIRST %26gt;%26gt;%26gt;\n\n");
break;
}
score = 1; // needed for "while (score)" to start off properly
setsEntered++;
fprintf (fd, "Values for scores Set # %d\n", setsEntered);
while ( score )
{
printf("Please Enter test Score %d: ", i+1);
score = atof(gets(buffer)); // atof instead of atoi - you really need float values not integers
if (buffer[0] == 0) break;
// initialize min score here (= first score)
if (0 == i) min = score;
if( score %26gt; max )
{ /* Find Max Score*/
max = score;
}
// "else" should not be here
if (score %26lt; min)
{ /* Find Min Score*/
min = score;
}
sum = score + sum; /* Find Sum Score*/
i++; // increment counter here
// write entry to file
fprintf (fd, " Score %d: %.1f\n", i, score);
}
average = sum/i; /* Find Average Score*/
// write statistics to file
fprintf(fd, "The average score is %.1f\n", average);
fprintf(fd, "Maximun Test Score = %.1f\n", max);
fprintf(fd, "Minimum Test Score = %.1f\n", min);
fprintf(fd, "---------------------------------------...
break;
case 'D':
case 'd':
printf( "\n\nThe average score is %.1f\n", average);
printf( "%d Test Scores\n", i );
printf( "Maximun Test Score = %.1f\n", max);
printf( "Minimum Test Score = %.1f\n", min);
printf( "\n\nPlease Clear Scores before preceding.");
break;
case 'Q':
case 'q':
eLoop=1;
break;
default:
printf("Please select a letter.\n");
break;
}
} while (eLoop!=1);
// close file
fclose (fd);
printf("Press Any Key.\n");
gets(buffer);
return 0;
}
Reply:You need to initialise
int setsEntered=0
float average = 0; (This is incase you do 'D' before entering any scores!
float min = 0; and add a check in the while loop
if ((min == 0) || (score %26lt; min)) { /* Find Min Score*/
min = score;
}
scoresEntered is not used
You are defining total within the case block but it is NOT used.
Initialise the values before the while loop after the case 'e' so you don't have to manually clear them each time before entering a set of scores.
sum = 0;
min = 0;
max = 0;
i = 0;
Increment the setsEntered when you actually enter the sets
case 'e':
setsEntered++;
while (score) {
You need to change the while (score) to a
do {
}while(score);
As at the end for the first set score is set to 0 so it never enters the while loop again.
I think that is it.
1. I have to have the user clear scores before entering the first set of test scores because the test score number starts of in the millions.
2. I can't get the program to enter a second set of numbers after the first set has been cleared.
3. How to get the program to count the sets as i enter them in. ( I will be saving them in a file)
#include %26lt;stdio.h%26gt;
#include %26lt;stdlib.h%26gt;
#include %26lt;math.h%26gt;
int main()
{
int eLoop=0,bsinp;
char menuResponse;
float score;
float average;
float x;
float max = 0;
float min = 1000;
float total = 0;
float sum;
int i = 0;
char buffer[BUFSIZ+1];
int scoresEntered;
int setsEntered;
do{
/*Print the Menu*/
printf ( "\n\n\**********************************...
printf ("*****Test Score Statisics v2.0*****\n");
printf ("***********************************\n"...
printf ("[C] Clear Stats\n");
printf ("[E] Enter Test Scores\n");
printf ("[D] Display Test Score Stats\n");
printf ("[Q] Quit\n\n");
printf ("Type the letter of your selection and press %26lt;ENTER%26gt;\n");
gets(buffer);
menuResponse = buffer[0];
switch (menuResponse)
{
/*Clear all scores and tally the total sets*/
case 'C':
case 'c':
printf("All Scores Cleared.\n");
setsEntered++;
max = 0;
min = 100;
int i = 0;
float total = 0;
break;
case 'E':
case 'e':
while ( score ) {
printf("Please Enter test Score %d: ", i+1);
score = atoi(gets(buffer));
i = i + 1;
if (buffer[0] == 0) break;
if( score %26gt; max ) { /* Find Max Score*/
max = score;
}else{
if (score %26lt; min) { /* Find Min Score*/
min = score;
}
}
sum = score + sum; /* Find Sum Score*/
}
average = sum / (i-1) ; /* Find Average Score*/
break;
case 'D':
case 'd':
printf( "\n\nThe average score is %.1f\n", average);
printf( "%d Test Scores\n", i-1 );
printf( "Maximun Test Score = %.1f\n", max);
printf( "Minimum Test Score = %.1f\n", min);
printf( "\n\nPlease Clear Scores before preceding.");
break;
case 'Q':
case 'q':
eLoop=1;
break;
default:
printf("Please select a letter.\n");
break;
}
}while (eLoop!=1);
printf("Press Any Key.\n");
gets(bsinp);
return 0;
}
Need help with c- programming?
sorry I'll just have to paste the full code here (commented where necessary). there were a few other flaws as well, also added support for writing sets to file. enjoy.
#include %26lt;stdio.h%26gt;
#include %26lt;stdlib.h%26gt;
#include %26lt;math.h%26gt;
int main()
{
int eLoop=0;
char menuResponse;
float score;
float average=0;
float max = 0;
float min = 0;
float sum=0;
int i = 0;
char buffer[BUFSIZ+1];
int setsEntered;
FILE *fd;
// open file where you put sets
if (NULL == (fd = fopen("mysets.txt", "w")))
{
printf ("\n Sorry couldn't open mysets.txt, change path or give permissions.\n");
exit(1);
}
do
{
/*Print the Menu*/
printf ( "\n\n***********************************...
printf ( "*****Test Score Statisics v2.0*****\n");
printf ( "***********************************\n")...
printf ("[C] Clear Stats\n");
printf ("[E] Enter Test Scores\n");
printf ("[D] Display Test Score Stats\n");
printf ("[Q] Quit\n\n");
printf ("Type the letter of your selection and press %26lt;ENTER%26gt;\n");
gets(buffer);
menuResponse = buffer[0];
switch (menuResponse)
{
/*Clear all scores and tally the total sets*/
case 'C':
case 'c':
printf("All Scores Cleared.\n");
max = 0;
min = 0;
i = 0;
sum = 0;
average = 0;
break;
case 'E':
case 'e':
if (0 != i)
{
printf (" %26lt;%26lt;%26lt; YOU MUST CLEAR PREVIOUS SCORES FIRST %26gt;%26gt;%26gt;\n\n");
break;
}
score = 1; // needed for "while (score)" to start off properly
setsEntered++;
fprintf (fd, "Values for scores Set # %d\n", setsEntered);
while ( score )
{
printf("Please Enter test Score %d: ", i+1);
score = atof(gets(buffer)); // atof instead of atoi - you really need float values not integers
if (buffer[0] == 0) break;
// initialize min score here (= first score)
if (0 == i) min = score;
if( score %26gt; max )
{ /* Find Max Score*/
max = score;
}
// "else" should not be here
if (score %26lt; min)
{ /* Find Min Score*/
min = score;
}
sum = score + sum; /* Find Sum Score*/
i++; // increment counter here
// write entry to file
fprintf (fd, " Score %d: %.1f\n", i, score);
}
average = sum/i; /* Find Average Score*/
// write statistics to file
fprintf(fd, "The average score is %.1f\n", average);
fprintf(fd, "Maximun Test Score = %.1f\n", max);
fprintf(fd, "Minimum Test Score = %.1f\n", min);
fprintf(fd, "---------------------------------------...
break;
case 'D':
case 'd':
printf( "\n\nThe average score is %.1f\n", average);
printf( "%d Test Scores\n", i );
printf( "Maximun Test Score = %.1f\n", max);
printf( "Minimum Test Score = %.1f\n", min);
printf( "\n\nPlease Clear Scores before preceding.");
break;
case 'Q':
case 'q':
eLoop=1;
break;
default:
printf("Please select a letter.\n");
break;
}
} while (eLoop!=1);
// close file
fclose (fd);
printf("Press Any Key.\n");
gets(buffer);
return 0;
}
Reply:You need to initialise
int setsEntered=0
float average = 0; (This is incase you do 'D' before entering any scores!
float min = 0; and add a check in the while loop
if ((min == 0) || (score %26lt; min)) { /* Find Min Score*/
min = score;
}
scoresEntered is not used
You are defining total within the case block but it is NOT used.
Initialise the values before the while loop after the case 'e' so you don't have to manually clear them each time before entering a set of scores.
sum = 0;
min = 0;
max = 0;
i = 0;
Increment the setsEntered when you actually enter the sets
case 'e':
setsEntered++;
while (score) {
You need to change the while (score) to a
do {
}while(score);
As at the end for the first set score is set to 0 so it never enters the while loop again.
I think that is it.
Setting up the Borland C++ compiler?
When setting up Borland C++ compiler these instructions come up
Open a console box.
1. Start | Run...
2. Type "command" into the field [Enter]
My question is what is a console box and how do you open it???
Setting up the Borland C++ compiler?
It means using Windows Command Prompt to set Borland C++ Compiler.
So, Goto Start Menu, and click RUN
Type:
cmd
if the OS is XP or
command
if the OS is 98 or so
and then press [ENTER] Key
You will now get the console (Command Prompt).
Reply:i think it means the command prompt. It should be in Start under accessories and you should see command prompt and that should open your "console box"
Open a console box.
1. Start | Run...
2. Type "command" into the field [Enter]
My question is what is a console box and how do you open it???
Setting up the Borland C++ compiler?
It means using Windows Command Prompt to set Borland C++ Compiler.
So, Goto Start Menu, and click RUN
Type:
cmd
if the OS is XP or
command
if the OS is 98 or so
and then press [ENTER] Key
You will now get the console (Command Prompt).
Reply:i think it means the command prompt. It should be in Start under accessories and you should see command prompt and that should open your "console box"
List all the elements of A * B where A = {a,b,c} and B = {1,2}.?
1) List all the elements of A * B where A = {a,b,c} and B = {1,2}.
2)Given the sets X ={24k +7 : k is an element of Z} , Y = {4n+3 : n is an element of Z}, V={6m+1 : m is an element of Z} , prove that X "is a subset of" Y and X "is a subset of" V but Y "is NOT a subset of" V .
3)If A, B, C are sets such that A "is a subset of" B and B "is a subset of" C , prove that A "is a subset of" C.
4) Is it true that if P(A) = P(B) for two sets A, B then A = B ?
Please give a reason and conclusion for each of the above as I am finding it very difficult to understand my teacher's silly notes!! thank you!!!
List all the elements of A * B where A = {a,b,c} and B = {1,2}.?
1) AXB is the set of ordered pairs (x, y) such that x is in A and y is in B.
AXB = {(a,1), (a,2), (b,1), (b,2), (c,1), (c,2)}
2)
X "is a subset of" Y : let a be an element of x.
Then a = 24K+7 = 24k + 4 + 3 = 4(6k + 1) + 3
Therefore a is an element of Y.
X "is a subset of" V : let b be an element of x.
Then b = 24K+7 = 24k + 6 + 1 = 6(4k + 1) + 1
Therefore b is an element of V.
Y "is NOT a subset of" V: 3 is an element of Y since 3 = 4(0)+3 but 3 is not an element of V because if you solve for m in 3=6m+1, you get m= 1/3 which is not Z.
3) You need to show that if a is in A, then it is in C too.
Choose a in A, then it must be in B as well.
Since B "is a subset of" C, then a also has to be in C. This proves that A "is a subset of" C.
4) I think it is true.
garland flower
2)Given the sets X ={24k +7 : k is an element of Z} , Y = {4n+3 : n is an element of Z}, V={6m+1 : m is an element of Z} , prove that X "is a subset of" Y and X "is a subset of" V but Y "is NOT a subset of" V .
3)If A, B, C are sets such that A "is a subset of" B and B "is a subset of" C , prove that A "is a subset of" C.
4) Is it true that if P(A) = P(B) for two sets A, B then A = B ?
Please give a reason and conclusion for each of the above as I am finding it very difficult to understand my teacher's silly notes!! thank you!!!
List all the elements of A * B where A = {a,b,c} and B = {1,2}.?
1) AXB is the set of ordered pairs (x, y) such that x is in A and y is in B.
AXB = {(a,1), (a,2), (b,1), (b,2), (c,1), (c,2)}
2)
X "is a subset of" Y : let a be an element of x.
Then a = 24K+7 = 24k + 4 + 3 = 4(6k + 1) + 3
Therefore a is an element of Y.
X "is a subset of" V : let b be an element of x.
Then b = 24K+7 = 24k + 6 + 1 = 6(4k + 1) + 1
Therefore b is an element of V.
Y "is NOT a subset of" V: 3 is an element of Y since 3 = 4(0)+3 but 3 is not an element of V because if you solve for m in 3=6m+1, you get m= 1/3 which is not Z.
3) You need to show that if a is in A, then it is in C too.
Choose a in A, then it must be in B as well.
Since B "is a subset of" C, then a also has to be in C. This proves that A "is a subset of" C.
4) I think it is true.
garland flower
Without setting-up a 501(c)(3), how can I collect tax-deductible contributions to assist in charity efforts?
I have researched setting up a 501(c)(3) non-profit which seems to be long and cumbersome. I was wondering how people seem to get set-up very quickly to collect tax-deductible contributions to assist others who unexpectedly have tragedies. Like "Mr. Johnson died last week. A tax-deductible contribution to his children can be made by sending a check to...."
There's no way that's a 501(c)(3) setup that quickly.
Without setting-up a 501(c)(3), how can I collect tax-deductible contributions to assist in charity efforts?
Contributions to a specific person are not tax deductible, so if you see a notation like you describe someplace, it's not true and if you donate then end up audited, it'll be disallowed.
There's no way that's a 501(c)(3) setup that quickly.
Without setting-up a 501(c)(3), how can I collect tax-deductible contributions to assist in charity efforts?
Contributions to a specific person are not tax deductible, so if you see a notation like you describe someplace, it's not true and if you donate then end up audited, it'll be disallowed.
A. (A – B) × C = (A × C) – (B × C).?
Prove each of the following statements where A, B, and C are sets and L, M, and N are
languages:
a. (A – B) × C = (A × C) – (B × C).
b. L∅ = ∅L = ∅.
c. Λ ∈ L if and only if L* = L+.
A. (A – B) × C = (A × C) – (B × C).?
wrong channel this isn't math 101
Reply:A?
languages:
a. (A – B) × C = (A × C) – (B × C).
b. L∅ = ∅L = ∅.
c. Λ ∈ L if and only if L* = L+.
A. (A – B) × C = (A × C) – (B × C).?
wrong channel this isn't math 101
Reply:A?
I need help with cache certificate in pre school setting c w?
wat could i write for unit 1
quetion m1 explain y adult interaction with children are importnant part of supporting their learning
i no its simpl but iv been wrtin 4 2 days now an i cant think lol
I need help with cache certificate in pre school setting c w?
You might want to practice your basic writing and spelling skills before you venture on to anything more complicated.
quetion m1 explain y adult interaction with children are importnant part of supporting their learning
i no its simpl but iv been wrtin 4 2 days now an i cant think lol
I need help with cache certificate in pre school setting c w?
You might want to practice your basic writing and spelling skills before you venture on to anything more complicated.
If n(C)=5, find n(D) and what other relationships exists between sets C and D?
d=6
If n(C)=5, find n(D) and what other relationships exists between sets C and D?
There is not enough information here, but one can come up with different postulates.
For example, let say that n represents a mathematical equation. If you had used n(x) = 5, most would have no problems saying that the function is a horizontal line crossing the y-axis at (0,5). I can just assume that n(C) is the same mathematical equation using C as the variable rather than x. Likewise for n(D). n(x)=n(C)=n(D)=5
Another example would be to consider n as a function that takes a capital alphabetic character and returns an integer. C is the 3rd member of the alphabet and the function returns the 3rd member of the set of odd integers. If the function n is a correlation between the set of alphabetic characters and the set of odd numbers, one could postulate that n(D) = 7.
blazing star
If n(C)=5, find n(D) and what other relationships exists between sets C and D?
There is not enough information here, but one can come up with different postulates.
For example, let say that n represents a mathematical equation. If you had used n(x) = 5, most would have no problems saying that the function is a horizontal line crossing the y-axis at (0,5). I can just assume that n(C) is the same mathematical equation using C as the variable rather than x. Likewise for n(D). n(x)=n(C)=n(D)=5
Another example would be to consider n as a function that takes a capital alphabetic character and returns an integer. C is the 3rd member of the alphabet and the function returns the 3rd member of the set of odd integers. If the function n is a correlation between the set of alphabetic characters and the set of odd numbers, one could postulate that n(D) = 7.
blazing star
If n(C)=5 find n(D)? What other relationships exists between sets C and D?
I think that is-
No of element of set C=5 then find the No of elements in D
This doesn't make any sense. Without proper Data Maths can never be solved
No of element of set C=5 then find the No of elements in D
This doesn't make any sense. Without proper Data Maths can never be solved
If n(C)=5, find n(D)? What other relationship exists between sets C and D?
sort yourself out mate, your not that clever are you this is genealogy/family history.
A,Band C are three sets.C is a subset of B ;n(AuBuC)=58; n(BuC)=35;n(BnC)=22;?
n(AnC)=10; n(A)=40 and n(B')=23 Draw a venn diagram to represent the information
A,Band C are three sets.C is a subset of B ;n(AuBuC)=58; n(BuC)=35;n(BnC)=22;?
Draw the Venn diagram with 3 circles A , B, and C overlapping.
since C is a subset of B then there are 22 items in C that are also in B (from B and C = 22 ) to place these into your diagram. of these 22 there will be 10 of the items in set A as A intersects C = 10...so place these into set A and set B and set C ==%26gt; this is the intersection of all the sets ! the remaining 12 go into C and B intersection. Since the complement of B is 23 that means that 23 items could be in A (or outside and in the universal set) and not in either C or B (cover up set B and then see where these 23 items will be placed in your drawing,,,not in C as that is all in B remember? so some of these 23 will be in A or some outside all the sets in the universal set...put them in A for now...then we will find out ...Since set A has 40 and B 35 there could be 13 in A and B (we already have 10 there in the intersection of all three sets and 13 in A and B but not C). The last piece is coming now...B union C has 35 so this means that there are 13 in B that are also in A ....and A has 40 (add in the intersection of all three and you will see what is missing ...there are 4 more in A that are not in B or in C) if there is a total of 58 in all then there must be 6 items floating outside of these sets in the universal set (check this from the complement of B)
The diagram should be completed now....when working a Venn Diagram it usually is best to start in the center at the intersection of all sets...then work out with the intersections of the sets 2 at a time and finally each set and then the remaining items that are not in any of the sets but are in the universal set .
This may sound confusing but if you draw the Venn and work it out from the inside and label as you go along..use a pencil as you may erase sometimes... :-) This will work.
Good Luck !
A,Band C are three sets.C is a subset of B ;n(AuBuC)=58; n(BuC)=35;n(BnC)=22;?
Draw the Venn diagram with 3 circles A , B, and C overlapping.
since C is a subset of B then there are 22 items in C that are also in B (from B and C = 22 ) to place these into your diagram. of these 22 there will be 10 of the items in set A as A intersects C = 10...so place these into set A and set B and set C ==%26gt; this is the intersection of all the sets ! the remaining 12 go into C and B intersection. Since the complement of B is 23 that means that 23 items could be in A (or outside and in the universal set) and not in either C or B (cover up set B and then see where these 23 items will be placed in your drawing,,,not in C as that is all in B remember? so some of these 23 will be in A or some outside all the sets in the universal set...put them in A for now...then we will find out ...Since set A has 40 and B 35 there could be 13 in A and B (we already have 10 there in the intersection of all three sets and 13 in A and B but not C). The last piece is coming now...B union C has 35 so this means that there are 13 in B that are also in A ....and A has 40 (add in the intersection of all three and you will see what is missing ...there are 4 more in A that are not in B or in C) if there is a total of 58 in all then there must be 6 items floating outside of these sets in the universal set (check this from the complement of B)
The diagram should be completed now....when working a Venn Diagram it usually is best to start in the center at the intersection of all sets...then work out with the intersections of the sets 2 at a time and finally each set and then the remaining items that are not in any of the sets but are in the universal set .
This may sound confusing but if you draw the Venn and work it out from the inside and label as you go along..use a pencil as you may erase sometimes... :-) This will work.
Good Luck !
Is frequent on and off of A/c through thermostat by setting on low temp will consume more electricity.?
Will it damage the compressor of a/c if we keep the setting at low temp. means if the room temp it 35 deg. and we set the temperature to 27 deg. it will cause the a/c to frequently on and off after reaching 2 deg below i.e 25 and will start again at 29 deg .will it consume more electricity. as it is said that a/c draws more electricity and load at the time starting.
Is frequent on and off of A/c through thermostat by setting on low temp will consume more electricity.?
Yes it can consume more power to switch on and off, but normally the power consumption with the constant on off is still less than continuous running due to the shear hours in operation. As for the compressor- this will not be an issue- do have it maintained regularly though.
I highly recommend taking steps to further insulate your home where possible, ie
Shut all doors and windows
Close curtains
For particularly sunny windows organise a sunshade or external blinds.
Alternatively can you change the setting on the aircon to give a slighly larger lee-way on the temp?
Reply:If your home is well insulated, the trick is to dial down your AC late at night when it's cool outside. In the morning, reset the thermostat to a desired temp and leave it alone. Constantly changing the setting is costly and unnecessary.
imperial
Is frequent on and off of A/c through thermostat by setting on low temp will consume more electricity.?
Yes it can consume more power to switch on and off, but normally the power consumption with the constant on off is still less than continuous running due to the shear hours in operation. As for the compressor- this will not be an issue- do have it maintained regularly though.
I highly recommend taking steps to further insulate your home where possible, ie
Shut all doors and windows
Close curtains
For particularly sunny windows organise a sunshade or external blinds.
Alternatively can you change the setting on the aircon to give a slighly larger lee-way on the temp?
Reply:If your home is well insulated, the trick is to dial down your AC late at night when it's cool outside. In the morning, reset the thermostat to a desired temp and leave it alone. Constantly changing the setting is costly and unnecessary.
imperial
Is there a way to send an email using C# without setting a SMTP Client?
I’m using .NET 2.0, and I want to send an email using C#. I am using the namespace System.Net.Mail to send email, but as far as I can tell it requiers you to use a SMTP Client. What I need to know is, is there a way to send an email without seting a SMTP Client? I could do this with PHP, but I don’t see how to do it in C#.
Is there a way to send an email using C# without setting a SMTP Client?
Hi,
You NEED an SMTP server to send email regardless of the programming/scripting language. The Send Mail Transport Protocol is the standard used for sending email across the internet.
The reason why this would work in PHP is because the SMTP server is already set on that machine, look at the php.ini and you will see all info. Most server operating systems has an SMTP server set by default, that is why your PHP works. Your webhost already set the SMTP server on your box.
For .NET, most hosts (if your doing web applications) have that already installed, but if your doing a normal application, then you have have an SMTP server to send the email. Usually, programmers supply an option in the program so the user can change the SMTP information so that the program could work. I usually allow the user add his email SMTP information into the settings of the program so that he/she could use the email features.
Good Luck
Is there a way to send an email using C# without setting a SMTP Client?
Hi,
You NEED an SMTP server to send email regardless of the programming/scripting language. The Send Mail Transport Protocol is the standard used for sending email across the internet.
The reason why this would work in PHP is because the SMTP server is already set on that machine, look at the php.ini and you will see all info. Most server operating systems has an SMTP server set by default, that is why your PHP works. Your webhost already set the SMTP server on your box.
For .NET, most hosts (if your doing web applications) have that already installed, but if your doing a normal application, then you have have an SMTP server to send the email. Usually, programmers supply an option in the program so the user can change the SMTP information so that the program could work. I usually allow the user add his email SMTP information into the settings of the program so that he/she could use the email features.
Good Luck
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